Electrophilic Aromatic Substitution 5. Introduction In this experiment, the directing effects of a bromo substituent was observed in the nitration by an electrophilic aromatic substitution reaction. The nitration was done with the addition of a nitric acid and sulfuric acid solution to bromobenzene, which was an exothermic reaction. When the reaction subsided, the mixture was heated before it was poured on ice and then neutralized to a pH of 8 with sodium carbonate. Liquid-liquid extraction was used to isolate the arene solution before it was analyzed through GC. The relative reactivities of different arenes in electrophilic aromatic bromination was also observed. In this part, five different arenes were reacted with a solution of acetic acid and bromine and the rates of reaction—determined by a change in color—were recorded. These reactions were done with a water bath. 6. Data and Results The retention time of the nitrated arene products were approximately 24.165, and 24.477 minutes. With the bromination, phenol was the first to change color, with the change occurring almost instantly at approximately half a second. The next arene to change was anisole, at approximately 15 seconds. The third was 4-bromophenol at 22 seconds, and then acetanilide at 34 seconds. Last to change color was diphenyl ether, at 340 seconds. 7. Discussion and …show more content…
Due to steric and inductive effects, the major product would be 1-bromo-2,4-dinitrobenzene and not 1-bromo-2,6-dinitrobenzene. This dinitration is undesired in the reaction and was prevented by performing the experiment below 60 °C. The nitro group already on the arene is strongly deactivating and so the activation energy required to add another nitro group is high. Thus, without a higher heat, the undesired reaction will not occur. Dinitration is also prevented by the precipitation of the para product, so that it is removed from the nitration
The sunset yellow dye had a faster and more linear reaction time than allura red; this could be caused by incorrect dilutions of the dye and
This is the result because The iodide displaces the chlorine forming 1-iodobutane. Since iodine is a much better leaving group than chlorine, 1-iodobutane will allow the cyanide ion to displace the leaving group much easier. The sodium ions will then ionically bond with the iodide ions to reform sodium iodide. This process lowers the total activation energy for the reaction. What would be the major product if 1,4-dibromo-4-methylpentane was allowed to react with one equivalent of NaI in Acetone?
The goal of the experiment is to synthesize a bromohexane compound from 1-hexene and HBr(aq) under reflux conditions and use the silver nitrate and sodium iodide tests to determine if the product is a primary or secondary hydrocarbon. The heterogeneous reaction mixture contains 1-hexene, 48% HBr(aq), and tetrabutylammonium bromide and was heated to under reflux conditions. Heating under reflux means that the reaction mixture is heated at its boiling point so that the reaction can proceed at a faster rate. The attached reflux condenser allows volatile substances to return to the reaction flask so that no material is lost. Since alkenes are immiscible with concentrated HBr, tetrabutylammonium bromide is used as a phase-transfer catalyst.
After 15-20 minutes, color separation became visible; red and blue were shown around the purple as well as blue/yellow around green. Solution line stopped at 60cm. Data and Observation The water/salt solution percolates faster than the alcohol/water solution. Alcohol & water solution:
Because p-nitrophenol is a yellow colored product, the reaction progress can be measured through measurements of the color intensity using a
The goal of this lab was to prepare methyl m-nitrobenzoate using electrophilic aromatic substitution using nitration. The reaction used methyl benzoate with the acid catalyst as sulfuric acid. The mechanism for the nitration using methyl benzoate is presented in Figure 1. Figure 1: Benzene can only undergo substitution reactions that are called electrophilic aromatic substitution reactions. Given that benzene rings are used commonly in the production of many organic compounds, the capability to make substitutions to benzene is critical.
Lecturer Date Introduction Theoretical Background Procedure The procedure was segmented into two categories, the reaction set up and the crude product isolation. Reaction set up The magnetic stirrer was prepared through placing it in the fume cupboard. 1 mmol of L-Phenylalanine was placed and weighed in a 5 mL conical vial.
Discussion This experiment done in lab was the Bromination of (E)-Stilbene to produce dibromide stilbene. Though there are three products, the meso-stilbene product is the major product. In order to get theunderstand how to get the correct major product, the full mechanism must be done.
In this lab, our hypothesis was proven for the most part. All primary colors (red, blue, and yellow) had no color change, while secondary colors (black, brown, green, purple) changed colors and had two or more dyes. The only exception to the statement was orange. While there is no orange dye, the dyes for yellow and red are so similar that there would be no change in color. Another possibility is that the dyes were not attracted to the solvent so they did not separate.
Nevertheless, the latter is not used in this experiment since it is very reactive and extremely flammable. On the contrary, NaBH4 is relatively mild and it can be used with protic solvents. In this manner, 1.507 grs of the ketone 9-fluorenone were mixed with 30.0 ml of 95% ethanol in a 125 ml Erlenmeyer flask. The bright yellow mixture was stirred during 7 minutes until all the components were dissolved.
The purpose of this experiment was to synthesize a Grignard reagent with 1-bromobutane and homogenized magnesium in anhydrous diethyl ether. This solution was refluxed in a flask connected to condenser and drying tube. As seen in the mechanism, maintaining a dry condition is important to avoid the Grignard reagent from attacking water, which will result in loss of the bromine. It is important to reduce the amount of moisture and water vapors to avoid destroying the Grignard reagent, which is essential to the synthesis of 2-methylhexanol.
The possible explanations and changes to make are similar to the previous questions. Conclusion and Future Experiment 18. The identity of the product and unknown were 4-tert-butylbenzyl phenol ether and tert-butyl phenol respectively. The key to making this discovery was the melting point and TLC results!
Dependent The time taken for the bluish -black color to fade away (color of Iodine solution mix with starch solution ). The rate of enzyme reaction Minutes (min) Table 1.1 – Table shows the controlled variables in the experiment variables Units Measures of controlled variables.
This is beneficial for reactivity because the nitrogen in -NH2 in aniline is able to delocalize the positive charge of a carbocation by donating its electrons to the carbon during the transition state when aniline is brominated. The next strongest substituent would be -OH in phenol, followed by -OCH3 in anisole. This is because the three hydrogens on the carbon make the carbon slightly electronegative, slightly pulling away the electrons surrounding the oxygen directly attached to the benzene ring. The least reactive substituent would be -NHCOCH3 in acetanilide because the highly electronegative oxygen pulls away electrons from the nitrogen directly attached to the benzene ring, making the nitrogen less willing to stabilize the carbocation in the transition state in an electrophilic aromatic substitution reaction. Since all of the substituents are orth, para-directos, bromine in a bromination reaction would be substituted at either the 2 carbon, 4 carbon, 2 and 4 carbon, 2 and 6 carbon, or 2, 4, and 6 carbon.
The nucleophile in this particular SN2 reaction was iodine and, as stated before, the leaving groups for 1-bromobutane and 1-chlorobutane are bromine and chlorine respectively. Bromine is a better leaving group than chlorine however, so the fact that 1-bromobutane reacted before 1-chlorobutane corresponds directly with what would be expected. As stated before, primary is more reactive than secondary and even more reactive that tertiary. This explains why no reaction/change was seen for 2-chlorobutane, 2-bromobutane, and tert-butyl-chloride. 2-bromobutane would have been expected to react next, due to bromine being a better leaving group than chlorine, then 2-chlorobutane.